The ULV 500 resistor is a high‑power, metal‑clad wire‑wound unit specified at 500W on a defined heatsink and commonly derated to roughly 300W in free air. With a nominal resistance of 75Ω and flying‑lead termination denoted by FL=500, these parts target braking, load‑bank and dynamic‑dump applications where robust pulse and thermal handling are required. This datasheet‑driven breakdown highlights which numbers drive selection: continuous power (heatsink vs free air), current/voltage limits, tolerance and TCR, thermal resistance implications, and mechanical/qualification notes. Below: background and token meaning, a quick spec table, electrical limits and worked current/voltage examples, thermal math and mounting guidance, mechanical/safety items, and a practical selection checklist.
Point: designers must translate rated watts into allowable current and realistic operating envelopes. Evidence: the stated 500W rating assumes a specific heatsink condition and FL=500 pins for connections. Explanation: subsequent sections show the I = sqrt(P/R) and V = I·R calculations, derating interpretation, and a compact checklist engineers can copy into procurement and test plans.
Point: model tokens encode form‑factor, power class and terminal style. Evidence: "ULV" signals a vertical metal‑clad, wire‑wound design optimized for high dissipation; "500" indicates the series power class; "FL=500" states flying‑lead length (typically 500 mm or a coded length) and related terminal preparation. Explanation: designers should parse tolerance suffixes (e.g., J for ±5%) and TCR codes on the part number to match precision or thermal drift needs.
| Token | Meaning for designers |
|---|---|
| ULV | Vertical metal‑clad, wire‑wound form factor for high power |
| 500 | Series power class (rated 500W on specified heatsink) |
| 75Ω | Nominal resistance value |
| J | Tolerance code (example: J = ±5%) |
| FL=500 | Flying leads / lead length specification |
| Feature | ULV 500 (Metal Clad) | Standard Ceramic | Thick Film Power |
|---|---|---|---|
| Heat Dissipation | Excellent (Active) | Moderate (Passive) | Poor (Requires PCB) |
| Pulse Handling | High (Wire-wound) | High | Low (Risk of failure) |
| Vibration Rating | Industrial Grade | Fragile | Moderate |
| Parameter | Typical value / note |
|---|---|
| Continuous power (heatsink) | 500W (per manufacturer heatsink condition) |
| Approx. free‑air power | ~300W (typical derate, application dependent) |
| Nominal resistance | 75Ω |
| Tolerance | e.g., J = ±5% (confirm datasheet) |
| TCR | Manufacturer TCR line (ppm/°C) — cite datasheet |
| Maximum working voltage | Refer to datasheet limit |
Point: rated power is conditional; evidence: 500W is specified for a defined heatsink condition, while free‑air operation is substantially lower. Explanation: use the fundamental formulas to translate power into allowable current and voltage for selection and protection settings.
// Calculation for 75Ω Load
At P = 500W: I = sqrt(500 / 75) = 2.582 A; V = 193.7 V
At P = 300W: I = sqrt(300 / 75) = 2.000 A; V = 150 V
"When deploying the ULV 500 in braking choppers, I've seen many fail because of 'Thermal Stacking'. If you mount multiple units side-by-side, you must derate them by an additional 20% unless you provide forced-air cooling of at least 2m/s. Also, always verify the lead temperature near the FL=500 junction; if the insulation feels brittle, you're exceeding the local thermal limit."
Scenario 1: Dynamic Braking Resistor for VFD Control.
Point: physical layout and lead length affect installation. Evidence: metal‑clad housing, bolt or lead mounting options, and FL=500 flying leads are called out. Explanation: extract dimensional callouts from the datasheet when designing PCBs or chassis cutouts; leave clearance for creepage and strain relief for flying leads to prevent fatigue or insulation compromise.
Common Mistake: Ignoring the ambient temperature inside the cabinet. If your cabinet reaches 50°C, the "300W free-air" rating may drop to 200W. Always use the derating curve provided in the official datasheet.
At the rated 500W heatsink condition the continuous current equals sqrt(500/75) ≈ 2.58 A (V ≈ 193.7 V). Under a typical free‑air derate near 300W the continuous current is 2.00 A.
Decide the maximum allowable component temperature and compute required θ_total = (Tmax − Tamb)/P. Select a heatsink that meet or beat that thermal resistance.